Physics · Refraction of light at plane and spherical surfaces, thin lens formula and lens maker formula

A converging beam of rays is incident on a diverging lens. Having passed through

A converging beam of rays is incident on a diverging lens. Having passed through the lens the rays intersect at a point \( 15 \mathrm{cm} \) from the lens on the opposite side. If the lens is removed the point where the rays meet will move 5 cm closer to the lens. The focal length of the lens is :

  • A. \( 5 \mathrm{cm} \)
  • B. -10 cm
  • C. \( 20 \mathrm{cm} \)
  • D. -30 cm

Step-by-step solution

The incident converging beam forms a virtual object for the diverging lens. Without the lens, the rays meet at a point 5 cm closer to the lens than with the lens. With lens, the rays meet at 15 cm on the opposite side (real image, v = +15 cm). Without lens, the convergence point is 10 cm from the lens (object distance, u = -10 cm, negative because virtual object). Using the lens formula 1/f = 1/u + 1/v with proper sign convention (u negative for virtual object, v positive for real image, f negative for diverging lens): 1/f = 1/(-10) + 1/15 = -1/10 + 1/15 = -1/30, so f = -30 cm.
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