A student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle screen and the lens as under: Position of candle Position of convex lens Position of the screen What will be the nature of the image formed if he further shifts the candle towards the lens?

Physics · Refraction of light at plane and spherical surfaces, thin lens formula and lens maker formula

A student focussed the image of a candle flame on a white screen using a convex

A student focussed the image of a candle flame on a white screen using a convex lens. He noted down the position of the candle screen and the lens as under: Position of candle \( =12.0 \mathrm{cm} \) Position of convex lens \( =\mathbf{5 0 . 0} \mathrm{cm} \) Position of the screen \( =88.0 \mathrm{cm} \) What will be the nature of the image formed if he further shifts the candle towards the lens?

A. Virtual and erect
B. Real and inverted
C. Real and diminishedd
D. None of the above

Step-by-step solution

The focal length of the lens is 19 cm (from lens formula 1/f = 1/v - 1/u with u = -38 cm, v = 38 cm). The object is initially at 2f. When the candle is moved further towards the lens, the object distance decreases. Once the object is placed within the focal length (i.e., less than 19 cm from the lens), the convex lens forms a virtual, erect, and magnified image. Since the shift is towards the lens, it will eventually be inside the focal point, so the image becomes virtual and erect.

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