Physics · Interference: Young's double-slit experiment and expression for fringe width, coherent sources and sustained interference of light
In a Young's double slit experiment, constructive interference is produced at a
In a Young's double slit experiment, constructive interference is produced at a certain point \( P . \) The intensities of light at \( \boldsymbol{P} \) due to the individual sources are 4 and 9 units. The resultant intensity at point \( \boldsymbol{P} \) will be-
- A. 13 units
- B. 25 units
- C. \( \sqrt{97} \) units
- D. 5 units
Step-by-step solution
For constructive interference, the phase difference is zero, so the resultant intensity is I = I1 + I2 + 2√(I1 I2) = (√I1 + √I2)^2. With I1 = 4, I2 = 9, √I1 = 2, √I2 = 3, sum = 5, square = 25 units.
Related MCQs
- In Young's experiment with white light, the central fringe is white. If now a transparent film is introduced in the upper beam coming from t…
- The condition for constructive interference is path difference should be equal to :…
- Initially interference is observed with the entire experimental set up inside a chamber filled with air, Now the chamber is evacuated. With …
- Two monochromatic (wavelength and coherent source of electromagnetic waves are placed on the -axis at the point \) and . \) A detector moves…
- Two coherent monochromatic light beams of intensities and are superposed. The maximum and minimum possible intensities in the resulting beam…