Physics · Oscillations of a spring: restoring force and force constant

When a body of mass is suspended from a certain light spring hanging vertically,

When a body of mass \( 1.0 \mathrm{kg} \) is suspended from a certain light spring hanging vertically, its length increases by \( 5 \mathrm{cm} . \) By suspending \( 2.0 \mathrm{kg} \) block to the spring and if the block is pulled through \( 10 \mathrm{cm} \) and released, the maximum velocity in it in \( m / s \) is

  • A. 0.5
  • B. 1
  • C. 2
  • D. 4

Step-by-step solution

Spring constant k = mg/x = (1 kg * 10 m/s^2)/(0.05 m) = 200 N/m. For 2 kg mass, angular frequency ω = sqrt(k/m) = sqrt(200/2)=10 rad/s. Amplitude A = 0.1 m. Maximum velocity v_max = Aω = 1 m/s.
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