Physics · Oscillations of a spring: restoring force and force constant
When a body of mass is suspended from a certain light spring hanging vertically,
When a body of mass \( 1.0 \mathrm{kg} \) is suspended from a certain light spring hanging vertically, its length increases by \( 5 \mathrm{cm} . \) By suspending \( 2.0 \mathrm{kg} \) block to the spring and if the block is pulled through \( 10 \mathrm{cm} \) and released, the maximum velocity in it in \( m / s \) is
- A. 0.5
- B. 1
- C. 2
- D. 4
Step-by-step solution
Spring constant k = mg/x = (1 kg * 10 m/s^2)/(0.05 m) = 200 N/m. For 2 kg mass, angular frequency ω = sqrt(k/m) = sqrt(200/2)=10 rad/s. Amplitude A = 0.1 m. Maximum velocity v_max = Aω = 1 m/s.
Related MCQs
- An object with a mass is suspended from an elastic spring with a spring constant k. The object oscillates with period T. If the mass of osci…
- A mass of is suspended from a spring of stiffness . It is set oscillating and it is observed that two successive oscillations have amplitude…
- Find force constant for small oscillation around equilibrium:…
- A light spiral spring supports a 200 g weight at its lower end. It oscillates up and down with a period of 1 sec. How much weight (gram) mus…
- In reality, a spring won't oscillate for ever. will the amplitude of oscillation until eventually the system is at rest.…