Physics · Pressure due to a fluid column, Pascal's law and its applications, effect of gravity on fluid pressure
If the air density were uniform, then the height of the atmosphere above the sea
If the air density were uniform, then the height of the atmosphere above the sea level to produce a normal atmospheric pressure of \( 1.0 \times 10^{5} \) Pa is (density of air is \( 1.3 \mathrm{kg} / \mathrm{m}^{3}, \mathrm{g}=10 \mathrm{m} / \mathrm{s}^{2} \) ):
- A. \( 0.77 \mathrm{km} \)
- B. 7.7 km
- C. \( 77 \mathrm{km} \)
- D. 0.077 km
Step-by-step solution
Using the formula for pressure due to a fluid column, P = ρgh, we solve for h: h = P/(ρg). Substituting P = 1.0 × 10^5 Pa, ρ = 1.3 kg/m^3, g = 10 m/s^2 gives h = (1.0 × 10^5) / (1.3 × 10) ≈ 7692.3 m = 7.6923 km ≈ 7.7 km.
Related MCQs
- 1atm…
- The area of cross section of the wider tube shown in figure is . If the boy standing on the piston weighs 45 kg, the difference in the level…
- Which of the following are the examples of atmospheric pressure?…
- The radii of the press plunger and the pump plunger are in the ratio If an effort of 32 kgf acts on the pump plunger. Find the maximum effor…
- Atmospheric pressure at sea level is…