Physics · Dimensions of Physics quantities, dimensional analysis and its applications
If the dimension of a physical quantity is given by \) then the physical quantit
If the dimension of a physical quantity is given by \( \left[M^{a} L^{b} T^{c}\right] \) then the physical quantity will be
- A. acceleration, if \( a=1, b=-1, c=-2 \)
- B. velocity, if \( a=1, b=0, c=-1 \)
- C. pressure, if \( a=1, b=-1, c=-2 \)
- D. force, if \( a=0, b=-1, c=-2 \)
Step-by-step solution
Pressure has dimensions of force per unit area: [M L T^{-2}] / [L^2] = [M L^{-1} T^{-2}], which matches M^1 L^{-1} T^{-2}. Option C gives a=1, b=-1, c=-2, which corresponds exactly to pressure. Options A, B, and D have incorrect exponents for acceleration, velocity, and force respectively.
Related MCQs
- The equation of a plane progressive wave is given by \) The dimension of \) is that of…
- Which of the following pair of quantities do not have the same dimensions?…
- A scientific way of doing things involve…
- The most basic rule of dimensional analysis is that of dimensional homogeneity. Only commensurable quantities may be…
- If the units of length and force are increased four times, then unit of energy will…