Physics · The potential energy of a spring, conservation of mechanical energy, conservative and non-conservative forces
A wire suspended vertically from one of its ends is stretched by attaching a wei
A wire suspended vertically from one of its ends is stretched by attaching a weight of \( 200 \mathrm{N} \) to the lower end. The weight stretches the wire by 1 mm. Then the energy stored in the wire is
- A. 0.1
- B. 0.2
- C. 10
- D. 20
Step-by-step solution
The energy stored in a stretched wire under elastic limit is given by (1/2) × force × extension. Here, force = 200 N, extension = 1 mm = 0.001 m. So, energy = 0.5 × 200 × 0.001 = 0.1 J.
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