2025 · Paper 2 · Physics

Question 3

The printed question, the official key, and each model’s JSON answer plus the reasoning it wrote.

PhysicsPaper 2Single correct

Q03

Official C

JEE Advanced 2025 Paper 2 Physics question 3

Model answers

Claude Fable 5.1

Anthropic

Correct3 / 3

C

Claude Fable 5.1 reasoning

Rod hinged at O, moment of inertia I = ml²/3. **Fig. 1:** Springs at midpoint (distance l/2) and top (distance l). For small angular displacement θ, restoring torque: τ₁ = k(l/2·θ)(l/2) + k(lθ)(l) = kl²θ(1/4 + 1) = (5/4)kl²θ So ω₁² = (5/4)kl²/I. **Fig. 2:** Both springs at midpoint (distance l/2): τ₂ = 2k(l/2·θ)(l/2) = (1/2)kl²θ So ω₂² = (1/2)kl²/I. Ratio: f₁/f₂ = √[(5/4)/(1/2)] = √(5/2) **Answer: (C)**

GPT 6 Astra

OpenAI

Correct3 / 3

C

GPT 6 Astra reasoning

No written reasoning was returned for this item.

GPT 5.6 Luna

OpenAI

Correct3 / 3

C

GPT 5.6 Luna reasoning

No written reasoning was returned for this item.