Mathematics · JEE

Medium Relations between roots and coefficients, nature of roots MCQs for JEE

12+ syllabus-aligned questions available

Quick answer

Medium Relations between roots and coefficients, nature of roots MCQs bridge basics and advanced JEE problems — 12+ available on Goodmarks.

Medium-difficulty Relations between roots and coefficients, nature of roots MCQs mirror typical JEE Main questions. Practise 12+ MCQs with step-by-step solutions.

Free sample questions

Attempt 8 free MCQs for Relations between roots and coefficients, nature of roots. Unlock 4+ more with Pro.

Unlock full bank
Q1MathsUnit 2: Complex Numbers and Quadratic Equations
If x+1x=4,x+\frac{1}{x}=4, then x4+1x4x^{4}+\frac{1}{x^{4}} is equal to
Q2MathsUnit 2: Complex Numbers and Quadratic Equations
If the product of two numbers is 10 and their sum is 7,7, which is the greatest of the two numbers?
Q3MathsUnit 2: Complex Numbers and Quadratic Equations
The zeros of the polynomial n3+9n2+n^{3}+9 n^{2}+ 23n+1523 n+15 are ad,aa-d, a and a+d.a+d . What is the value of 'a'?
Q4MathsUnit 2: Complex Numbers and Quadratic Equations
Discriminant of the equation 3x2+-3 x^{2}+ 2x8=02 x-8=0 is
Q5MathsUnit 2: Complex Numbers and Quadratic Equations
If the sum of the roots of the equation ax2+bx+c=0a x^{2}+b x+c=0 is equal to sum of the squares of their reciprocals, then bc2,ca2,ab2b c^{2}, c a^{2}, a b^{2} are in
Q6MathsUnit 2: Complex Numbers and Quadratic Equations
If xy=7x-y=7 and x3y3=133;x^{3}-y^{3}=133 ; find: the value of xyx y
Q7MathsUnit 2: Complex Numbers and Quadratic Equations
Find pRp \in R for x2px+p+3=0x^{2}-p x+p+3=0 has
Q8MathsUnit 2: Complex Numbers and Quadratic Equations
Assertion Let equations ax2+bx+c=a x^{2}+b x+c= 0(a,b,cR)&x2+2x+5=0\mathbf{0}(\boldsymbol{a}, \boldsymbol{b}, \boldsymbol{c} \in \boldsymbol{R}) \& \boldsymbol{x}^{2}+\mathbf{2} \boldsymbol{x}+\mathbf{5}=\mathbf{0} have common root, then a+cb=13\frac{\boldsymbol{a}+\boldsymbol{c}}{\boldsymbol{b}}=\frac{\mathbf{1}}{\mathbf{3}} Reason If both roots of Ax2+Bx+K1=0&A x^{2}+B x+K_{1}=0 \& Ax2+Bx+K2=0\boldsymbol{A}^{\prime} \boldsymbol{x}^{2}+\boldsymbol{B}^{\prime} \boldsymbol{x}+\boldsymbol{K}_{2}=\mathbf{0} are identical thenAA1=BB1=K1K2( where A,B,K1\operatorname{then} \frac{\boldsymbol{A}}{\boldsymbol{A}_{1}}=\frac{\boldsymbol{B}}{\boldsymbol{B}_{1}}=\frac{\boldsymbol{K}_{1}}{\boldsymbol{K}_{2}}\left(\text { where } \boldsymbol{A}, \boldsymbol{B}, \boldsymbol{K}_{1}\right. and A,B,K2R)\left.A^{\prime}, B,^{\prime} K_{2} \in R\right)

Want unlimited Relations between roots and coefficients, nature of roots practice?

Pro unlocks the full question bank, topic filters, and attempt history.

Frequently asked questions

Are medium Relations between roots and coefficients, nature of roots MCQs enough for JEE Main?

Yes for many units — combine with PYQ-style and mock tests as exam day approaches.