Mathematics · JEE

Meaning of P(n,r) and C(n,r) Concepts for JEE

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Quick answer

Master Meaning of P(n,r) and C(n,r) by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Meaning of P(n,r) and C(n,r) before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Meaning of P(n,r) and C(n,r) is a core JEE Main Mathematics subtopic under Permutations and Combinations. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

  • Understand the definition and scope of Meaning of P(n,r) and C(n,r) in the JEE syllabus
  • Memorise key formulas and standard results linked to Meaning of P(n,r) and C(n,r)
  • Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

  • Revise Meaning of P(n,r) and C(n,r) with a one-page formula sheet before attempting mixed tests
  • After each practice set, log mistakes specific to Meaning of P(n,r) and C(n,r) and reattempt after 48 hours

Common trap

Students often rush Meaning of P(n,r) and C(n,r) questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Permutations and Combinations in JEE Main Mathematics.

Free sample questions

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Q1MathsUnit 4: Permutations and Combinations
Arrange the following values of nn in ascending order. A:nP5=nP6n=\boldsymbol{A}:^{n} \boldsymbol{P}_{5}=^{n} \boldsymbol{P}_{6} \Rightarrow \boldsymbol{n}= B:nP12=nP8n=\boldsymbol{B}:^{\boldsymbol{n}} \boldsymbol{P}_{12}=^{\boldsymbol{n}} \boldsymbol{P}_{\boldsymbol{8}} \Rightarrow \boldsymbol{n}= C:nC(n3)=10n=\boldsymbol{C}:^{n} \boldsymbol{C}_{(\boldsymbol{n}-\mathbf{3})}=\mathbf{1 0} \Rightarrow \boldsymbol{n}= D:(n+1)P5:nP6=1:2n=\boldsymbol{D}:^{(\boldsymbol{n}+1)} \boldsymbol{P}_{5}:^{\boldsymbol{n}} \boldsymbol{P}_{6}=\mathbf{1}: \boldsymbol{2} \Rightarrow \boldsymbol{n}=
Q2MathsUnit 4: Permutations and Combinations
If r>1,r>1, then nPrnCr\frac{n P_{r}}{n C_{r}} is This question has multiple correct options
Q3MathsUnit 4: Permutations and Combinations
If nPr=30240^{n} \boldsymbol{P}_{r}=\mathbf{3 0 2 4 0} and nCr=252,^{n} \boldsymbol{C}_{r}=\mathbf{2 5 2}, then the ordered pair (n,r)(n, r) is equal to:
Q4MathsUnit 4: Permutations and Combinations
If nC3=nC9,^{n} C_{3}=^{n} C_{9}, then nC2=^{n} C_{2}=

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