Mathematics · JEE

Simple applications Revision for JEE

24+ syllabus-aligned questions available

Quick answer

Revise Simple applications by covering every subtopic once, drilling formulas, then solving 24+ timed MCQs with full solutions.

Use this Simple applications revision checklist before mocks and the final exam. Reinforce concepts with 24+ syllabus-aligned MCQs on Goodmarks.

Revision checklist

  1. 1.Core idea: Simple applications
  2. 2.Relates to other subtopics in Permutations and Combinations
  3. 3.Fundamental counting principle
  4. 4.Permutations with/without repetition
  5. 5.Master Simple applications definitions and standard results
  6. 6.Solve 20 timed MCQs for Simple applications

Syllabus context

Part of Permutations and Combinations in JEE Main Mathematics.

Free sample questions

Attempt 8 free MCQs for Simple applications. Unlock 16+ more with Pro.

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Q1MathsUnit 4: Permutations and Combinations
The total number of ways of formation of five letter words from the letters of the word INDEPENDENT,I N D E P E N D E N T, is
Q2MathsUnit 4: Permutations and Combinations
There are 4 balls of different colours &4\& 4 boxes of colours same as those of the balls. The number of ways in which the balls, one in each box, could be placed such that exactly no ball go to the box of its own colour is:
Q3MathsUnit 4: Permutations and Combinations
All the five digit numbers that can be formed using the digits 1,2,3,4,5 without repetition, are arranged in the decreasing order of magnitude. The rank of the number 34215 is
Q4MathsUnit 4: Permutations and Combinations
7 boys and 8 girls have to sit in a row on 15 chairs numbered from 1 to 15 then?
Q5MathsUnit 4: Permutations and Combinations
Find the correct co-related number. 5:36::6:?\mathbf{5}: \mathbf{3 6}:: \mathbf{6}: ?
Q6MathsUnit 4: Permutations and Combinations
Assertion In the shop there are five types of ice- creams available, a child buys six ice- creams. Reason The number of different ways the child can buy the six ice-creams is 10C3^{10} C_{3}
Q7MathsUnit 4: Permutations and Combinations
A 5 digit number divisible by 3 is to be formed using the numerals 0,1,2,3,4 \& 5 without repetition. The total number of ways this can be done is
Q8MathsUnit 4: Permutations and Combinations
Given: 20!18!=380\frac{20 !}{18 !}=380

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Frequently asked questions

How should I revise Simple applications before JEE?

Follow the checklist on this page, revise formulas daily, and attempt mixed MCQs every 2–3 days.