Mathematics · JEE

One-one, into and onto functions MCQs for JEE

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One-one, into and onto functions JEE MCQs on Goodmarks include 13+ multiple-choice questions with correct answers and step-by-step solutions. Attempt free samples below or unlock the full bank with Pro.

Master One-one, into and onto functions through exam-style multiple-choice questions. This page features 13+ JEE MCQs covering One-one, into and onto functions, each with verified answers and clear explanations.

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Q1MathsUnit 1: Sets, Relations and Functions
If f:[0,)[0,),\mathbf{f}:[\mathbf{0}, \infty) \rightarrow[\mathbf{0}, \infty), and f(x)=x1+x\mathbf{f}(\mathbf{x})=\frac{\mathbf{x}}{\mathbf{1}+\mathbf{x}} then f\boldsymbol{f} is
Q2MathsUnit 1: Sets, Relations and Functions
Let f:RR\boldsymbol{f}: \boldsymbol{R} \rightarrow \boldsymbol{R} where f(x)=2x2x\boldsymbol{f}(\boldsymbol{x})=\boldsymbol{2}^{|\boldsymbol{x}|}-\boldsymbol{2}^{-\boldsymbol{x}} then f(x)f(x) is
Q3MathsUnit 1: Sets, Relations and Functions
The function f:(,1)(0,e5]\boldsymbol{f}:(-\infty,-1) \rightarrow\left(\mathbf{0}, e^{5}\right] defined by f(x)=ex33x+2f(x)=e^{x^{3}-3 x+2} is
Q4MathsUnit 1: Sets, Relations and Functions
If a function f:(2,)B\boldsymbol{f}:(2, \infty) \rightarrow \boldsymbol{B} defined by f(x)=x24x+5f(x)=x^{2}-4 x+5 is a bijection, then B=\boldsymbol{B}=
Q5MathsUnit 1: Sets, Relations and Functions
Let A={x,y,z},B={a,b,c}\boldsymbol{A}=\{\boldsymbol{x}, \boldsymbol{y}, \boldsymbol{z}\}, \boldsymbol{B}=\{\boldsymbol{a}, \boldsymbol{b}, \boldsymbol{c}\} and f\boldsymbol{f} ABA \rightarrow B be defined by f(x)=a,f(y)=f(x)=a, f(y)= b,f(z)=c.\boldsymbol{b}, \boldsymbol{f}(\boldsymbol{z})=\boldsymbol{c} . This function is
Q6MathsUnit 1: Sets, Relations and Functions
If f(A)f(A) is a proper subset of BB, then ff ABA \rightarrow B is called a/an ..\ldots \ldots . . function
Q7MathsUnit 1: Sets, Relations and Functions
An identity function is a?
Q8MathsUnit 1: Sets, Relations and Functions
f:QQ\boldsymbol{f}: \boldsymbol{Q} \rightarrow \boldsymbol{Q} is defined by f(x)=15x+7\boldsymbol{f}(\boldsymbol{x})=\mathbf{1 5} \boldsymbol{x}+\mathbf{7} is

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