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Calculation of standard deviation, variance and mean deviation for grouped and ungrouped data Short Tricks for JEE

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Short tricks for Calculation of standard deviation, variance and mean deviation for grouped and ungrouped data work only with strong fundamentals. Apply the tips below in timed sets and review every explanation.

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Syllabus context

Part of Statistics and Probability in JEE Main Mathematics.

Free sample questions

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Q1MathsUnit 13: Statistics and Probability
In an experiment with 15 observations on x,x, then following results were available: ∑x2=2830,∑x=170\sum x^{2}=2830, \sum x=170 One observation that was 20 was found to be wrong and was replaced by the correct value 30.30 . Then the corrected variance is:
Q2MathsUnit 13: Statistics and Probability
Find variance for following data:  Class 0−10−20−3010203040\begin{array}{lllll}\text { Class } & 0- & 10- & 20- & 30 \\ & 10 & 20 & 30 & 40\end{array} frequency ey 6 8
Q3MathsUnit 13: Statistics and Probability
The variance of observations 112,116,120,125,132 is
Q4MathsUnit 13: Statistics and Probability
The variance of the data 6,8,10,12,14,16,18,20,22,24 is
Q5MathsUnit 13: Statistics and Probability
Variance remains unchanged by change of
Q6MathsUnit 13: Statistics and Probability
Which of the following are dimensionless
Q7MathsUnit 13: Statistics and Probability
Assertion If rxy\boldsymbol{r}_{\boldsymbol{x} \boldsymbol{y}} i.e. r(x,y)=0.25,σx=0.1,σy=\boldsymbol{r}(\boldsymbol{x}, \boldsymbol{y})=\mathbf{0 . 2 5}, \boldsymbol{\sigma}_{\boldsymbol{x}}=\mathbf{0 . 1}, \boldsymbol{\sigma}_{\boldsymbol{y}}= 4,4, then byx=10b_{y x}=10 Reason byx=rσyσx\boldsymbol{b}_{\boldsymbol{y} \boldsymbol{x}}=\boldsymbol{r} \frac{\boldsymbol{\sigma}_{\boldsymbol{y}}}{\boldsymbol{\sigma}_{\boldsymbol{x}}}
Q8MathsUnit 13: Statistics and Probability
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