Physics · JEE

Reactance and impedance, LCR series circuit, resonance, power in AC circuits, wattless current Mock Test for JEE

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Q1PhysicsUnit 14: Electromagnetic Induction and Alternating Currents
The current flowing through the resistor in a series LCR a.c. circuit, is I=ε/R\boldsymbol{I}=\varepsilon / \boldsymbol{R} Now the inductor and capacitor are connected in parallel and joined in series with the resistor as shown in figure. The current in the circuit is now. (Symbols have their usual meaning)
Q2PhysicsUnit 14: Electromagnetic Induction and Alternating Currents
In series LCR circuit R=18ΩR=18 \Omega and impedance is 33Ω33 \Omega. An r.m.s. voltage 220V220 V is applied across the circuit. The true power consumed in a.c. circuit is
Q3PhysicsUnit 14: Electromagnetic Induction and Alternating Currents
A circuit consists of a resistor,an inductor and a capacitor connected in series. If the resistance of a resistor is 25Ω25 \Omega and the value of inductive reactance is equal to capacitive reactance, then the net impedance of the circuit will be :

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