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Hard Viscosity, Stoke's law, terminal velocity, streamline and turbulent flow, critical velocity MCQs for JEE

21+ syllabus-aligned questions available

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Hard Viscosity, Stoke's law, terminal velocity, streamline and turbulent flow, critical velocity MCQs train multi-concept problem solving — attempt after mastering easy and medium sets (21+ on Goodmarks).

Push your limits with hard Viscosity, Stoke's law, terminal velocity, streamline and turbulent flow, critical velocity MCQs designed for JEE Advanced-level thinking. 21+ questions with detailed solutions.

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Part of Properties of Solids and Liquids in JEE Main Physics.

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Attempt 8 free MCQs for Viscosity, Stoke's law, terminal velocity, streamline and turbulent flow, critical velocity. Unlock 13+ more with Pro.

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Q1PhysicsUnit 7: Properties of Solids and Liquids
Assertion A liquid will flow faster and more smoothly from a sealed can when two holes are punched in the can than when one hole is punched. Reason The flow becomes streamlined with two holes rather than with one hole.
Q2PhysicsUnit 7: Properties of Solids and Liquids
Will a parachute work in vacuum?
Q3PhysicsUnit 7: Properties of Solids and Liquids
According to Stoke's law, the viscous drag force, on an oil drop is proportional to:
Q4PhysicsUnit 7: Properties of Solids and Liquids
A marble of mass xx and diameter 2r2 r is gently released a tall cylinder containing honey.If the marble displaces mass $$y(⟨1,x)\$ \$ y(\langle 1, x) of the liquid then the terminal velocity is proportional to
Q5PhysicsUnit 7: Properties of Solids and Liquids
A small metal ball of diameter 4 mm and density 10.5g/cm310.5 g / c m^{3} in dropped in glycerine of density 1.5g/cm3.1.5 g / c m^{3} . The ball attains a terminal velocity of 8cm/sec8 \mathrm{cm} / \mathrm{sec} The coefficient of viscosity of glycerine is
Q6PhysicsUnit 7: Properties of Solids and Liquids
A good lubricant should be highly
Q7PhysicsUnit 7: Properties of Solids and Liquids
Due to air a falling body faces a resistive force proportional to square of velocity v,v, consequently its effective downward acceleration is reduced and is given by a=g−kv2a=g-k v^{2} where k=k= 0.002m−1.0.002 m^{-1} . The terminal velocity of the falling body is (in⁡m/s)(\operatorname{in} \mathrm{m} / \mathrm{s})
Q8PhysicsUnit 7: Properties of Solids and Liquids
The rain drops falling from the sky neither injure us nor make holes on the ground because they move with:

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