Chemistry · Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium
For the system }+\mathbf{2} \boldsymbol{B}_{(\boldsymbol{g})} \rightleftharpoons
For the system \( \boldsymbol{A}_{(g)}+\mathbf{2} \boldsymbol{B}_{(\boldsymbol{g})} \rightleftharpoons \boldsymbol{C}_{(g)}, \) the equilibrium concentrations are \( \boldsymbol{A}=\mathbf{0 . 0 6} \boldsymbol{m o l} \boldsymbol{L}^{-1} \) \( \boldsymbol{B}=\mathbf{0 . 1 2} \boldsymbol{m o l} \boldsymbol{L}^{-1} \) \( \boldsymbol{C}=\mathbf{0 . 2 1 6} \boldsymbol{m o l} \boldsymbol{L}^{-1} \) Then \( K_{c} \) for the reaction is
- A. 250
- B. 416
- C. 450 \)
- D. 525
Step-by-step solution
The equilibrium constant Kc for the reaction A(g) + 2B(g) ⇌ C(g) is given by Kc = [C]/([A][B]^2). Substituting the given concentrations: [C]=0.216 M, [A]=0.06 M, [B]=0.12 M. Compute denominator: [A][B]^2 = 0.06 * (0.12)^2 = 0.06 * 0.0144 = 0.000864. Then Kc = 0.216 / 0.000864 = 250.
Related MCQs
- for this reaction is 10. If 1,2,3,4 mole/litre of and respectively are present in a container at the direction of reaction will be:…
- The equilibrium constant for a reaction is and the reaction quotient is . For a reaction mixture, the ratio is 0.33 This means that:…
- For the following equilibrium, in gaseous phase, is of the total volume when equilibrium is set up. Hence, percent of dissociation of is:…
- For } \rightleftharpoons \boldsymbol{X} \boldsymbol{Y}_{(\boldsymbol{g})}+\boldsymbol{Y}_{(\boldsymbol{g})}, \) intially 1 mole each of and …
- One mole of ethanol is treated with one mole of ethanoic acid at One-forth of the acid changes into ester at equilibrium. The equilibrium co…