Maths · Arithmetic and Geometric progressions
3 years ago, the sum of the ages of a father and his son was 40 yeas. After 2 ye
3 years ago, the sum of the ages of a father and his son was 40 yeas. After 2 years, the sum of their ages will be
- A. 46 years
- B. 40 years
- C. 50 years
- D. 60 years
Step-by-step solution
Let current ages be F (father) and S (son). Three years ago: (F-3)+(S-3)=40 => F+S=46. After 2 years: (F+2)+(S+2)=F+S+4=46+4=50.
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