Maths · Arithmetic and Geometric progressions
The value of a machine depreciates at the rate of every year. it was purchased 3
The value of a machine depreciates at the rate of \( 10 \% \) every year. it was purchased 3 years ago. If its present value is Rs. 8748 , its purchase price was
- A. Rs. 10000
- B. Rs. 11372
- C. Rs. 12000
- D. Rs. 12500
Step-by-step solution
The machine depreciates at 10% per year, so its value after t years is P * (0.9)^t. Given present value after 3 years is Rs. 8748, we have P * (0.9)^3 = 8748. Since (0.9)^3 = 0.729, P = 8748 / 0.729 = 12000.
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