Maths · Arithmetic and Geometric progressions
By what least number 4320 be multiplied to become a perfect cube?
By what least number 4320 be multiplied to become a perfect cube?
- A. 10
- B. 30
- C. 20
- D. 50
Step-by-step solution
Prime factorize 4320: 4320 = 432 × 10 = (2^4 × 3^3) × (2 × 5) = 2^5 × 3^3 × 5^1. For a perfect cube, exponents must be multiples of 3. Here, 2 needs exponent (6-5)=1 more, 3 is already multiple, 5 needs (3-1)=2 more. So multiply by 2^1 × 5^2 = 2 × 25 = 50.
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