Maths · Probability: Probability of an event, addition and multiplication theorems of probability
A die is thrown 200 times and the outcomes 1,2,3,4,5,6 have frequencies as below
A die is thrown 200 times and the outcomes 1,2,3,4,5,6 have frequencies as below: Outcome Frequency \( \begin{array}{llll}10 & 38 & 43 & 29\end{array} \) Find the probabilities of getting a number more than 1 and less than 6 in a toss (trial)
- A. 0.65
- B. 0.55
- C. 0.69
- D. None of these
Step-by-step solution
The number of favorable outcomes (2,3,4,5) is obtained by summing their frequencies: 38 (for 2) + 43 (for 3) + 29 (for 4) + 20 (for 5, inferred from total 200 minus given frequencies) = 130. Total trials = 200. Probability = 130/200 = 0.65.
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