Maths · Probability: Probability of an event, addition and multiplication theorems of probability
Two coins are tossed once, where (i) tail appears on one coin, one coin shows he
Two coins are tossed once, where (i) \( E: \) tail appears on one coin, \( \boldsymbol{F}: \) one coin shows head (ii) \( E: \) no tail appears, \( \boldsymbol{F}: \) no head appears Determine \( \boldsymbol{P}(\boldsymbol{E} \mid \boldsymbol{F}) \)
- A. 1,0
- B. 1,0.2
- C. 0,2
- D. 1,3
Step-by-step solution
For part (i): Sample space = {HH, HT, TH, TT}. E = {HT, TH} (one tail), F = {HT, TH} (one head). Since E = F, P(E|F) = 1. For part (ii): E = {HH} (no tail), F = {TT} (no head). Intersection empty, so P(E|F) = 0. Thus the pair is (1,0).
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