Physics · Binding energy per nucleon and its variation with mass number, nuclear fission and fusion
f a proton and anti-proton come close to each other and annihilate, how much ene
f a proton and anti-proton come close to each other and annihilate, how much energy will be released?
- A. \( 1.5 \times 10^{-10} \mathrm{J} \)
- B. \( 3 \times 10^{-10} J \)
- C. \( 4.5 \times 10^{-10} J \)
- D. \( 2 \times 10^{-10} \mathrm{J} \)
Step-by-step solution
The energy released comes from the rest mass energy of the proton and antiproton. Each has mass m_p = 1.67 × 10^{-27} kg. Using E = mc^2, total energy = 2 m_p c^2 = 2 × 1.67 × 10^{-27} kg × (3 × 10^8 m/s)^2 = 3 × 10^{-10} J.
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