Physics · Binding energy per nucleon and its variation with mass number, nuclear fission and fusion
If energy required to remove one of the two electron from He atom is then what i
If energy required to remove one of the two electron from He atom is \( 29.5 e V \) then what is the value of energy required to convert a helium atom into \( \boldsymbol{\alpha}- \) particle?
- A. \( 54.4 e V \)
- B. \( 83.9 e V \)
- C. \( 29.5 e V \)
- D. 24.9eV
Step-by-step solution
Removing one electron from He (first ionization) requires 29.5 eV. The second ionization removes the remaining electron from He⁺, which is hydrogen-like with Z=2. The binding energy for He⁺ is 13.6 × Z² = 13.6 × 4 = 54.4 eV. The total energy to remove both electrons (forming α-particle) is 29.5 eV + 54.4 eV = 83.9 eV.
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