Physics · Semiconductors, semiconductor diode: I-V characteristics in forward and reverse bias, diode as a rectifier
In common base circuit of a transistor, current amplification factor is 0.95 Cal
In common base circuit of a transistor, current amplification factor is 0.95 Calculate the emitter current if base current is \( 0.2 \mathrm{mA} \)
- A. \( 2 \mathrm{mA} \)
- B. \( 4 \mathrm{m} \)
- C. 6 m A \)
- D. \( 8 \mathrm{m} \)
Step-by-step solution
In a common base transistor, current amplification factor α = I_C / I_E. Also, I_E = I_B + I_C. Substituting I_C = α I_E gives I_E = I_B + α I_E, so I_E (1 - α) = I_B, hence I_E = I_B / (1 - α) = 0.2 mA / (1 - 0.95) = 0.2 / 0.05 = 4 mA.