Physics · Uniformly accelerated motion, velocity-time, position-time graph, relations for uniformly accelerated motion, relative velocity
A ball thrown in the air reaches a height of and drops down to the ground. Find
A ball thrown in the air reaches a height of \( 10 \mathrm{m} \) and drops down to the ground. Find the time taken by the ball to complete this entire journey.
- A. \( 2.78 \mathrm{sec} \)
- B. 3.40 sec
- C. 1.43 sec
- D. 2.86 sec
Step-by-step solution
Using g = 9.8 m/s², the initial speed u = √(2gh) = √(2 × 9.8 × 10) = √196 = 14 m/s. Time to reach maximum height t₁ = u/g = 14/9.8 = 1.4286 s. Total time for upward and downward journey T = 2t₁ = 2 × 1.4286 = 2.8572 s ≈ 2.86 s.
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