Physics · Uniformly accelerated motion, velocity-time, position-time graph, relations for uniformly accelerated motion, relative velocity
What will be the ratio of the distances moved by a freely falling body from rest
What will be the ratio of the distances moved by a freely falling body from rest in 4 th and 5 th seconds of journey
- A. 4: 5
- B. 7: 9
- C. 16: 25
- D. 1: 1
Step-by-step solution
For a freely falling body from rest, the distance covered in the nth second is given by s_n = (g/2)(2n-1). For n=4, s_4 = (g/2)(7); for n=5, s_5 = (g/2)(9). The ratio s_4:s_5 = 7:9.
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