Physics · Motion in a plane, projectile motion, uniform circular motion
A particle projected from the origin \) moves in plane so that its velocity is \
A particle projected from the origin \( (x=y=0) \) moves in \( x y \) plane so that its velocity is \( v=(2 \hat{i}+4 x \hat{j}) \mathrm{m} / \mathrm{s}, \) when it is at point \( (x, y) \) m. \( (\hat{i} \text { and } \hat{j} \) are the unit vectors along \( x \) and \( y \) axis). What is the value of \( y, \) when \( x=3 \)
- A. 15
- B. 10
- C. 9 \)
- D. 8
Step-by-step solution
Given v_x = dx/dt = 2, so x = 2t (since starts at origin). v_y = dy/dt = 4x = 8t, so y = 4t^2 = (x^2). For x=3, y=9.
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