Physics · Motion in a plane, projectile motion, uniform circular motion
In the two dimensional motions:
In the two dimensional motions:
- A. \( x-t \) graph gives actual path of the particle
- B. \( y-t \) graph gives actual path of the particle
- C. \( \sqrt{x^{2}+y^{2}} \) versus t graph gives the actual path of the particle
- D. \( y-x \) graph gives actual path of particle
Step-by-step solution
The path of a particle in two-dimensional motion is the trajectory in the plane, which is given by the relationship between its x and y coordinates. The y-x graph plots y against x, directly showing the shape of the path. In contrast, x-t and y-t graphs show position components as functions of time, not the path, and the distance vs time graph does not reveal the path's geometry. Therefore, option D is correct.
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