Chemistry · JEE

Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units Previous Year Questions for JEE

7+ syllabus-aligned questions available

Quick answer

Goodmarks offers 7+ JEE-style PYQs for Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units with detailed solutions. While official past papers rotate yearly, our bank covers the same concepts, difficulty, and question formats tested in JEE Chemistry.

Previous year questions are the fastest way to understand how Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units is tested in JEE. Practise 7+ exam-pattern MCQs modelled on JEE Main and Advanced, with full solutions for every question.

Syllabus context

Part of Chemical Kinetics in JEE Main Chemistry.

Free sample questions

Attempt 7 free MCQs for Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units. Unlock the full bank with Pro.

Unlock full bank

Q1ChemistryUnit 8: Chemical Kinetics

A reaction

A+B \rightarrow C

is second order with respect to

A

and independent of

B

The rate expression for the reaction is:

Q2ChemistryUnit 8: Chemical Kinetics

Statement - I : The molecularity of the reaction

\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow 2 \mathrm{HBr}

is 2 Statement - II: The order of this reaction is

3 / 2

Q3ChemistryUnit 8: Chemical Kinetics

The choices below are some of the proposed steps of a reaction mechanism. Which step is least likely to be the ratedetermining step of the mechanism?

Q4ChemistryUnit 8: Chemical Kinetics

Which one of the following statements for order of reaction is not correct?

Q5ChemistryUnit 8: Chemical Kinetics

In the hydrolysis of organic chloride in the presence of a large excess of water,

\boldsymbol{R C l}+\boldsymbol{H}_{2} \boldsymbol{O} \rightarrow \boldsymbol{R O H}+\boldsymbol{H} \boldsymbol{C l}

Q6ChemistryUnit 8: Chemical Kinetics

For the reaction given below,

\mathbf{2} \mathbf{O}_{\mathbf{3}}(\mathbf{g}) \rightarrow \mathbf{3} \mathbf{O}_{\mathbf{2}}(\mathbf{g})

\operatorname{Step} \mid: \mathbf{O}_{3}(\mathbf{g}) \rightarrow \mathbf{O}_{2}(\mathbf{g})+\mathbf{O}(\mathbf{g})

Step

2: \mathrm{O}_{3}(\mathrm{g})+\mathrm{O} \rightarrow^{\text {slow }} 2 \mathrm{O}_{2}(\mathrm{g})

Statement I: The molecularity of the first step is 1 and of the second step is 2 Statement-II:

O(g)

is an intermediate and rate of reaction is

\mathbf{K}\left[\mathbf{O}_{3}\right]^{2}\left[\mathbf{O}_{2}\right]^{-1}

and order of reaction is 1

Q7ChemistryUnit 8: Chemical Kinetics

Which of the following statement is true for the reaction,

\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow \boldsymbol{2} \boldsymbol{H} \boldsymbol{B} \boldsymbol{r}

The rate law is

\frac{\boldsymbol{d} \boldsymbol{x}}{\boldsymbol{d} \boldsymbol{t}}=\boldsymbol{k}\left[\boldsymbol{H}_{2}\right]\left[\boldsymbol{B} \boldsymbol{r}_{2}\right]^{1 / 2}

Want unlimited Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units practice?

Pro unlocks the full question bank, topic filters, and attempt history.

Get started free View Pro plans

Frequently asked questions

Why practise PYQs for Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units?

PYQs reveal recurring concepts, common traps, and the difficulty level JEE expects. Solving them builds exam temperament and time management.

Does Goodmarks have actual JEE past papers?

Our bank includes exam-style MCQs aligned with JEE Main Chemistry syllabus for Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units, covering the same topics as previous year papers.

How should I use PYQs for Chemical Kinetics?

Solve timed sets, review every explanation, note weak subtopics, then revisit with focused practice on Goodmarks.

Are PYQ solutions step-by-step?

Yes. Every question includes the correct answer and a detailed explanation showing the reasoning.