Chemistry · JEE

Delta G° (Standard Gibbs energy change) and equilibrium constant Concepts for JEE

3+ syllabus-aligned questions available

Quick answer

Master Delta G° (Standard Gibbs energy change) and equilibrium constant by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Delta G° (Standard Gibbs energy change) and equilibrium constant before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Delta G° (Standard Gibbs energy change) and equilibrium constant is a core JEE Main Chemistry subtopic under Chemical Thermodynamics. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

Understand the definition and scope of Delta G° (Standard Gibbs energy change) and equilibrium constant in the JEE syllabus
Memorise key formulas and standard results linked to Delta G° (Standard Gibbs energy change) and equilibrium constant
Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

Revise Delta G° (Standard Gibbs energy change) and equilibrium constant with a one-page formula sheet before attempting mixed tests
After each practice set, log mistakes specific to Delta G° (Standard Gibbs energy change) and equilibrium constant and reattempt after 48 hours

Common trap

Students often rush Delta G° (Standard Gibbs energy change) and equilibrium constant questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Chemical Thermodynamics in JEE Main Chemistry.

Free sample questions

Attempt 3 free MCQs for Delta G° (Standard Gibbs energy change) and equilibrium constant. Unlock the full bank with Pro.

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Q1ChemistryUnit 4: Chemical Thermodynamics

The plot shows the variation of

-\ln \boldsymbol{K}_{\boldsymbol{p}}

versus temperature for the two reactions.

M(s)+\frac{1}{2} O_{2}(g) \rightarrow M O(s)

and

C(s)+\frac{1}{2} O_{2}(g) \rightarrow C O(s)

Identify the correct statement?

Q2ChemistryUnit 4: Chemical Thermodynamics

toppr Q Type your question At the point of intersection of

A l_{2} U_{3}

and

M g O

curves

(A), \triangle G^{0}

becomes zero for the reaction,

\frac{2}{3} A l_{2} O_{3}+2 M g \rightarrow+\frac{4}{3} A l

Below this point, magnesium can reduce alumina. Although thermodynamically feasible, Al is not used for reduction of

M g O

because:

Q3ChemistryUnit 4: Chemical Thermodynamics

A schematic plot of

\ln \boldsymbol{K}_{e q}

. versus inverse of temperature for a reaction is shown below: The reaction must be:

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Frequently asked questions

What concepts in Delta G° (Standard Gibbs energy change) and equilibrium constant are essential for JEE?

Focus on core ideas across Delta G° (Standard Gibbs energy change) and equilibrium constant. JEE tests application, not just memorisation.