Chemistry · JEE

Medium Delta G° (Standard Gibbs energy change) and equilibrium constant MCQs for JEE

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Medium Delta G° (Standard Gibbs energy change) and equilibrium constant MCQs bridge basics and advanced JEE problems — 3+ available on Goodmarks.

Medium-difficulty Delta G° (Standard Gibbs energy change) and equilibrium constant MCQs mirror typical JEE Main questions. Practise 3+ MCQs with step-by-step solutions.

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Q1ChemistryUnit 4: Chemical Thermodynamics
The plot shows the variation of lnKp-\ln \boldsymbol{K}_{\boldsymbol{p}} versus temperature for the two reactions. M(s)+12O2(g)MO(s)M(s)+\frac{1}{2} O_{2}(g) \rightarrow M O(s) and C(s)+12O2(g)CO(s)C(s)+\frac{1}{2} O_{2}(g) \rightarrow C O(s) Identify the correct statement?
Q2ChemistryUnit 4: Chemical Thermodynamics
toppr Q Type your question At the point of intersection of Al2U3A l_{2} U_{3} and MgOM g O curves (A),G0(A), \triangle G^{0} becomes zero for the reaction, 23Al2O3+2Mg+43Al\frac{2}{3} A l_{2} O_{3}+2 M g \rightarrow+\frac{4}{3} A l Below this point, magnesium can reduce alumina. Although thermodynamically feasible, Al is not used for reduction of MgOM g O because:
Q3ChemistryUnit 4: Chemical Thermodynamics
A schematic plot of lnKeq\ln \boldsymbol{K}_{e q}. versus inverse of temperature for a reaction is shown below: The reaction must be:

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