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Equilibrium involving chemical processes: Law of chemical equilibrium, equilibrium constants (Kp and Kc) and their significance, the significance of Delta G and Delta G° in chemical equilibrium Mock Test for JEE

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Q1ChemistryUnit 6: Equilibrium
One mole of ethanol is treated with one mole of ethanoic acid at 25.25 . One-forth of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be:
Q2ChemistryUnit 6: Equilibrium
2 moles of PCl5P C l_{5} when heated in a closed vessels of 2 litre capacity at equilibrium 40%40 \% of PCl5P C l_{5} dissociated in PCl3P C l_{3} and Cl2.C l_{2} . What is the value of the equilibrium constant?
Q3ChemistryUnit 6: Equilibrium
56g56 \mathrm{g} of nitrogen and 8g8 \mathrm{g} of hydrogen gas are heated in a closed vessel. At equilibrium, 34 g of ammonia are present. The equilibrium number of moles of nitrogen, hydrogen and ammonia are respectively:
Q4ChemistryUnit 6: Equilibrium
A+BC+D,KcA+B \rightleftharpoons C+D, K_{c} for this reaction is 10. If 1,2,3,4 mole/litre of A,B,CA, B, C and DD respectively are present in a container at 25C,25^{\circ} C, the direction of reaction will be:
Q5ChemistryUnit 6: Equilibrium
For the system A(g)+2B(g)C(g),\boldsymbol{A}_{(g)}+\mathbf{2} \boldsymbol{B}_{(\boldsymbol{g})} \rightleftharpoons \boldsymbol{C}_{(g)}, the equilibrium concentrations are A=0.06molL1\boldsymbol{A}=\mathbf{0 . 0 6} \boldsymbol{m o l} \boldsymbol{L}^{-1} B=0.12molL1\boldsymbol{B}=\mathbf{0 . 1 2} \boldsymbol{m o l} \boldsymbol{L}^{-1} C=0.216molL1\boldsymbol{C}=\mathbf{0 . 2 1 6} \boldsymbol{m o l} \boldsymbol{L}^{-1} Then KcK_{c} for the reaction is
Q6ChemistryUnit 6: Equilibrium
A flask containing 0.5 atm pressure of A2(g),A_{2}(g), some solid ABA B added into flask which undergoes dissociation according to : 2AB(s)A2(g)+B2(g)\boldsymbol{2} \boldsymbol{A} \boldsymbol{B}(\boldsymbol{s}) \rightleftharpoons \boldsymbol{A}_{2}(\boldsymbol{g})+\boldsymbol{B}_{2}(\boldsymbol{g}) Kp=0.06atm2.\boldsymbol{K}_{\boldsymbol{p}}=\mathbf{0 . 0 6} \boldsymbol{a t m}^{2} . The total pressure (in atm) at equilibrium is :
Q7ChemistryUnit 6: Equilibrium
What is the partial pressure (atm) of HI in the equilibrium mixture?
Q8ChemistryUnit 6: Equilibrium
Which is not a reversible reaction?
Q9ChemistryUnit 6: Equilibrium
The equilibrium constant Kp( in atm )K_{p}(\text { in atm }) for the reaction is 9 at 7 at mm and 300K300 K A2(g)B2(g)+C2(g)\boldsymbol{A}_{2}(\boldsymbol{g}) \rightleftharpoons \boldsymbol{B}_{2}(\boldsymbol{g})+\boldsymbol{C}_{2}(\boldsymbol{g}) Calculate the average molar mass (in gm/mol\mathrm{gm} / \mathrm{mol} ) of an equilibrium mixture: Given Molar of A2,B2A_{2}, B_{2} and C2C_{2} are 70,49 \& 21 gm/ mol respectively.
Q10ChemistryUnit 6: Equilibrium
At some temperature and under a pressure of 4 atm, PCl5P C l_{5} is 10%10 \% dissociated. Calculate the pressure at which PCl5P C l_{5} will be 20%20 \% dissociated, temperature remaining same.
Q11ChemistryUnit 6: Equilibrium
For the equilibrium N2+3H2N_{2}+3 H_{2} \rightleftharpoons 2NH3,K6\mathbf{2} N \boldsymbol{H}_{3}, \boldsymbol{K}_{6} at 1000K1000 \mathrm{K} is 2.37×103\mathbf{2 . 3 7} \times \mathbf{1 0}^{-3} Equilibrium [N2]=2.M[H2]=3M\left[N_{2}\right]=2 . M\left[H_{2}\right]=3 M the concentration of NH3\boldsymbol{N} \boldsymbol{H}_{3} is:
Q12ChemistryUnit 6: Equilibrium
At 90C,90^{\circ} C, the following equilibrium is established H2(g)+S(s)H2S(g)Kp=6.8×\boldsymbol{H}_{2}(\boldsymbol{g})+\boldsymbol{S}(s) \rightleftharpoons \boldsymbol{H}_{2} \boldsymbol{S}(\boldsymbol{g}) \boldsymbol{K}_{\boldsymbol{p}}=\mathbf{6 . 8} \times 102\mathbf{1 0}^{\mathbf{2}} If 0.2 mol of hydrogen and 1.0 mol of sulphur are heated to 90C90^{\circ} \mathrm{C} in a 1.0 litre vessel, what will be the partial pressure of H2S\boldsymbol{H}_{2} \boldsymbol{S} at equilibrium?
Q13ChemistryUnit 6: Equilibrium
If 8g8 g mol of PCl5P C l_{5} heated in a closed vessel of 10L10 L capacity and 25%25 \% of its dissociates into PCl3P C l_{3} and Cl2C l_{2} at the equilibrium then value of Kp\boldsymbol{K}_{\boldsymbol{p}} will be equal to:
Q14ChemistryUnit 6: Equilibrium
The virial equation for 1 mole of a real gas is written as: PV=RTP V=R T \left[1+\frac{A}{V}+\frac{B}{V^{2}}+\frac{C}{V^{3}}+\ldots . . . . . . . . . . to the higher \right. power of n]n] Where A,BA, B and CC are known as virial coefficients. If Vander Waal's equation is written in virial form, then what will be the value of B?
Q15ChemistryUnit 6: Equilibrium
For XY2(g)XY(g)+Y(g),\boldsymbol{X} \boldsymbol{Y}_{\mathbf{2}(\boldsymbol{g})} \rightleftharpoons \boldsymbol{X} \boldsymbol{Y}_{(\boldsymbol{g})}+\boldsymbol{Y}_{(\boldsymbol{g})}, intially 1 mole each of XY2X Y_{2} and yy are present in 10L flask at 500mm.lf the equilibrium pressure of XY\mathrm{XY} is 150mm,Kp150 \mathrm{mm}, K_{p} is?

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