Chemistry · JEE

Chemical equations and stoichiometry Concepts for JEE

47+ syllabus-aligned questions available

Quick answer

Master Chemical equations and stoichiometry by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

Build clear conceptual foundations for Chemical equations and stoichiometry before speed practice. This guide covers what JEE expects and how to test yourself with MCQs.

Concept explainer

Chemical equations and stoichiometry is a core JEE Main Chemistry subtopic under Some Basic Concepts in Chemistry. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

Understand the definition and scope of Chemical equations and stoichiometry in the JEE syllabus
Memorise key formulas and standard results linked to Chemical equations and stoichiometry
Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

Revise Chemical equations and stoichiometry with a one-page formula sheet before attempting mixed tests
After each practice set, log mistakes specific to Chemical equations and stoichiometry and reattempt after 48 hours

Common trap

Students often rush Chemical equations and stoichiometry questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Syllabus context

Part of Some Basic Concepts in Chemistry in JEE Main Chemistry.

Free sample questions

Attempt 8 free MCQs for Chemical equations and stoichiometry. Unlock 39+ more with Pro.

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Q1ChemistryUnit 1: Some Basic Concepts in Chemistry

Volume of

N_{2},

in litres, liberated on heating 6.4 g of

N H_{4} N O_{2}

is:

Q2ChemistryUnit 1: Some Basic Concepts in Chemistry

On dividing 0.46 by

15.374,

the actual answer is

0.02992 .

The correctly reported answer will be:

Q3ChemistryUnit 1: Some Basic Concepts in Chemistry

Equation for the following reaction.

\boldsymbol{C u}+\boldsymbol{x} \boldsymbol{H} \boldsymbol{N} \boldsymbol{O}_{3} \rightarrow \boldsymbol{C u}\left(\boldsymbol{N} \boldsymbol{O}_{3}\right)_{2}+

2 H_{2} O+2 N O_{y}

Find the value of

x

and

y

Q4ChemistryUnit 1: Some Basic Concepts in Chemistry

heated together, the maximum weight of

C l_{2}

gas evolved will be:

Q5ChemistryUnit 1: Some Basic Concepts in Chemistry

In the reaction

4 N H_{3}+5 O_{2} \longrightarrow

4 N O+6 H_{2} O,

when one mole of ammonia and one mole of oxygen are made to react to completion, then

Q6ChemistryUnit 1: Some Basic Concepts in Chemistry

White phosphorous reacts with limited chlorine and the product is hydrolyzed in the presence of water. What would be the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water?

Q7ChemistryUnit 1: Some Basic Concepts in Chemistry

\boldsymbol{F} \boldsymbol{e}_{\boldsymbol{x}} \boldsymbol{O}_{3}(\boldsymbol{s})+\boldsymbol{2} \boldsymbol{A} \boldsymbol{l}(\boldsymbol{s}) \rightarrow \boldsymbol{2} \boldsymbol{F} \boldsymbol{e}(\boldsymbol{l})+

\boldsymbol{A l}_{2} \boldsymbol{O}_{\boldsymbol{y}}(\boldsymbol{s})+\boldsymbol{H} \boldsymbol{e} \boldsymbol{a} \boldsymbol{t}

Find the value of

x

and

y

Q8ChemistryUnit 1: Some Basic Concepts in Chemistry

The standard solution of sodium hydroxide cannot be prepared by direct weighing of cold sodium hydroxide because it is :

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Frequently asked questions

What concepts in Chemical equations and stoichiometry are essential for JEE?

Focus on core ideas across Chemical equations and stoichiometry. JEE tests application, not just memorisation.