Chemistry · JEE

Easy Chemical equations and stoichiometry MCQs for JEE

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Part of Some Basic Concepts in Chemistry in JEE Main Chemistry.

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Q1ChemistryUnit 1: Some Basic Concepts in Chemistry

Volume of

N_{2},

in litres, liberated on heating 6.4 g of

N H_{4} N O_{2}

is:

Q2ChemistryUnit 1: Some Basic Concepts in Chemistry

On dividing 0.46 by

15.374,

the actual answer is

0.02992 .

The correctly reported answer will be:

Q3ChemistryUnit 1: Some Basic Concepts in Chemistry

Equation for the following reaction.

\boldsymbol{C u}+\boldsymbol{x} \boldsymbol{H} \boldsymbol{N} \boldsymbol{O}_{3} \rightarrow \boldsymbol{C u}\left(\boldsymbol{N} \boldsymbol{O}_{3}\right)_{2}+

2 H_{2} O+2 N O_{y}

Find the value of

x

and

y

Q4ChemistryUnit 1: Some Basic Concepts in Chemistry

heated together, the maximum weight of

C l_{2}

gas evolved will be:

Q5ChemistryUnit 1: Some Basic Concepts in Chemistry

In the reaction

4 N H_{3}+5 O_{2} \longrightarrow

4 N O+6 H_{2} O,

when one mole of ammonia and one mole of oxygen are made to react to completion, then

Q6ChemistryUnit 1: Some Basic Concepts in Chemistry

White phosphorous reacts with limited chlorine and the product is hydrolyzed in the presence of water. What would be the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water?

Q7ChemistryUnit 1: Some Basic Concepts in Chemistry

\boldsymbol{F} \boldsymbol{e}_{\boldsymbol{x}} \boldsymbol{O}_{3}(\boldsymbol{s})+\boldsymbol{2} \boldsymbol{A} \boldsymbol{l}(\boldsymbol{s}) \rightarrow \boldsymbol{2} \boldsymbol{F} \boldsymbol{e}(\boldsymbol{l})+

\boldsymbol{A l}_{2} \boldsymbol{O}_{\boldsymbol{y}}(\boldsymbol{s})+\boldsymbol{H} \boldsymbol{e} \boldsymbol{a} \boldsymbol{t}

Find the value of

x

and

y

Q8ChemistryUnit 1: Some Basic Concepts in Chemistry

The standard solution of sodium hydroxide cannot be prepared by direct weighing of cold sodium hydroxide because it is :

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