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Online Practice: Covalent bond fission: Homolytic and heterolytic, free radicals, carbocations and carbanions, stability of carbocations and free radicals, electrophiles and nucleophiles for JEE

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Sharpen your chemistry preparation with interactive online practice for Covalent bond fission: Homolytic and heterolytic, free radicals, carbocations and carbanions, stability of carbocations and free radicals, electrophiles and nucleophiles. Goodmarks offers 11+ JEE-style MCQs mapped to the official syllabus, each with detailed explanations so you learn from every attempt.

Syllabus context

Part of Some Basic Principles of Organic Chemistry in JEE Main Chemistry.

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Attempt 8 free MCQs for Covalent bond fission: Homolytic and heterolytic, free radicals, carbocations and carbanions, stability of carbocations and free radicals, electrophiles and nucleophiles. Unlock 3+ more with Pro.

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Q1ChemistryUnit 14: Some Basic Principles of Organic Chemistry
ln⁡SN1,\ln S_{N} 1, the first step involves the formation of:
Q2ChemistryUnit 14: Some Basic Principles of Organic Chemistry
Which of the following is organometalic compound
Q3ChemistryUnit 14: Some Basic Principles of Organic Chemistry
In the figure below, the plane drawn behind the peptide bond indicates the:
Q4ChemistryUnit 14: Some Basic Principles of Organic Chemistry
The first transition state in the overall exothermic addition of HBr to propane resembles the intermediate (carbocation). Choose the best phrase to complete the following statement The second transition states (for addition of Br−B r^{-} to the carbocation):
Q5ChemistryUnit 14: Some Basic Principles of Organic Chemistry
The total number of electrons in the carbon atom of methyl free radical is:
Q6ChemistryUnit 14: Some Basic Principles of Organic Chemistry
Which of the following statements is correct? rhis question has multiple correct options
Q7ChemistryUnit 14: Some Basic Principles of Organic Chemistry
Which of the following free radicals is the most stable?
Q8ChemistryUnit 14: Some Basic Principles of Organic Chemistry
Arrange in the order of nucleophilicity: HO−,CH3O−,CH3≡\boldsymbol{H O}^{-}, \boldsymbol{C H}_{3} \boldsymbol{O}^{-}, \boldsymbol{C H}_{3} \equiv C−,CH3COO−\boldsymbol{C}^{-}, \boldsymbol{C} \boldsymbol{H}_{3} \boldsymbol{C O O}^{-}

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