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Electrical energy and power, electrical resistivity and conductivity Short Tricks for JEE

30+ syllabus-aligned questions available

Quick answer

Short tricks for Electrical energy and power, electrical resistivity and conductivity work only with strong fundamentals. Apply the tips below in timed sets and review every explanation.

Use these Electrical energy and power, electrical resistivity and conductivity shortcuts to save time in JEE Physics papers — then validate speed with 30+ MCQs on Goodmarks.

Short tricks for speed

  • Electrical energy and power, electrical resistivity and conductivity focus drill

    Solve 15 mixed MCQs for Electrical energy and power, electrical resistivity and conductivity, review every explanation, and note formulas you hesitated on.

  • Dimensional check first

    Before solving, verify each term has consistent SI dimensions — eliminates wrong options quickly in JEE MCQs.

  • Limiting cases

    Substitute extreme values (t→0, m→∞, θ→0) to sanity-check your final expression.

Syllabus context

Part of Current Electricity in JEE Main Physics.

Free sample questions

Attempt 8 free MCQs for Electrical energy and power, electrical resistivity and conductivity. Unlock 22+ more with Pro.

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Q1PhysicsUnit 12: Current Electricity
In the circuit shown, the heat produced in 5Ω5 \Omega resistor is 10 calorie/sec. The heat produced/sec in 4Ω4 \Omega resistor will be :
Q2PhysicsUnit 12: Current Electricity
Q Type your question- and of fixed emf, the resistor R1\boldsymbol{R}_{1} has fixed resistance and the resistance of resistor R2\boldsymbol{R}_{2} can be varied (but R2\boldsymbol{R}_{2} is always nonzero). Then the electric power delivered to the resistor of resistance R1R_{1} is independent of the value of resistance R2\boldsymbol{R}_{2} Reason f potential difference across a fixed resistance is unchanged, the power delivered to the resistor remains constant.
Q3PhysicsUnit 12: Current Electricity
The most important safety method used for protecting home appliances from short circuiting or overloading is
Q4PhysicsUnit 12: Current Electricity
The electrical energy in kilowatt hours consumed in operating ten 50 W50 ~ W bulbs for 10 hrs/day in a month of 30 days is
Q5PhysicsUnit 12: Current Electricity
The Joules heating effect for an electric heater in A.CA . C and in D.C. circuit is
Q6PhysicsUnit 12: Current Electricity
The heat developed in a system is proportional to the current through it. Then
Q7PhysicsUnit 12: Current Electricity
A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be:
Q8PhysicsUnit 12: Current Electricity
P=V2RP=\frac{V^{2}}{R} is applied when

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Frequently asked questions

Are short tricks enough for Electrical energy and power, electrical resistivity and conductivity in JEE?

No — tricks complement concepts. Master the theory first, then use shortcuts in timed MCQ practice.

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