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Capacitance of a parallel plate capacitor with and without dielectric medium between the plates, energy stored in a capacitor Mock Test for JEE

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Part of Electrostatics in JEE Main Physics.

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Q1PhysicsUnit 11: Electrostatics

In a parallel plate capacitor, the capacitance:

Q2PhysicsUnit 11: Electrostatics

A parallel plate condenser with plate separation d is charged with the help of battery so that

V_{0}

energy is stored in the system. The battery is now removed. a plate of dielectric constant k and thickness d is placed between the plates of condenser. The new energy of the system will be :

Q3PhysicsUnit 11: Electrostatics

The insertion of a dielectric between the plates of a parallel-plate capacitor always

Q4PhysicsUnit 11: Electrostatics

A parallel plate air capacitor has capacity

^{\prime} C^{\prime}

farad, potential

^{\prime} V^{\prime}

volt and energy'

E^{\prime}

joule. When the gap between the plates is completely filled with dielectric.

Q5PhysicsUnit 11: Electrostatics

The capacity of a parallel plate condenser is inversely proportional to

Q6PhysicsUnit 11: Electrostatics

A parallel plate capacitor of capacitance

6 \mu F

in air and

60 \mu F

When dielectric is introduced. What is the dielectric constant of the medium.?

Q7PhysicsUnit 11: Electrostatics

Fill in the blank: In order to increase the capacity of a parallel plate condenser, one should introduce a sheet of between the plates (assume that the space is completely filled).

Q8PhysicsUnit 11: Electrostatics

A parallel plate condenser with a dielectric of dielectric constant

\boldsymbol{K}

between the plates has a capacity

C

and is charged to a potential

V

volt. The dielectric slab is slowly removed from between the plates and then reinserted. The net work done by the system in this process is :

Q9PhysicsUnit 11: Electrostatics

A capacitor of

10 \mu F

capacitance is charged by a

12 V

battery. Now the space between the plates of capacitors is filled with a dielectric of dielectric constant

K=3

and again it is charged. The magnitude of the charge is :

Q10PhysicsUnit 11: Electrostatics

The capacity of a parallel plate condenser is

10 \mu F

without the dielectric. Material with a dielectric constant of 2 is used to fill half- thickness between the plates. The new capacitance is

\mu F

Q11PhysicsUnit 11: Electrostatics

The energy stored in magnetic field produced by a metal sphere is 4.5 J. If the sphere contains

4 \mu C

charge, its radius will be :

\left[\text { Take }: \frac{1}{4 \pi \epsilon_{0}}=9 \times 10^{9} N-m^{2} / C^{2}\right]

Q12PhysicsUnit 11: Electrostatics

The capacitance of a parallel-plate capacitor is

C_{0}

when the region between the plates has air. This region is now filled with a dielectric slab of dielectric constant K. The capacitor is connected to a cell emf

\varepsilon_{1}

and the slab is taken out. This question has multiple correct options

Q13PhysicsUnit 11: Electrostatics

The breakdown field strength for dry air is

3 \times 10^{6} \mathrm{V} / \mathrm{m}

. Each of the plates of the parallel plate capacitor has an area of

0.2 m^{2} .

The maximum charge that can be collected is : (Given permittivity of air

\left.\epsilon_{\circ}=8.85 \times 10^{-12} C^{2} / N m^{2}\right)

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