Physics · JEE

Electric flux, Gauss's law and its applications to find field due to infinitely long uniformly charged straight wire, uniformly charged infinite plane sheet and uniformly charged thin spherical shell Mock Test for JEE

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Syllabus context

Part of Electrostatics in JEE Main Physics.

Free sample questions

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Q1PhysicsUnit 11: Electrostatics

The electric field at a distance

\frac{3 R}{2}

from the centre of a charged conducting spherical shell of radius

\mathrm{R}

\mathrm{E}

. The electric field at a distance

\frac{\boldsymbol{R}}{\mathbf{2}}

from the centre of the sphere is :

Q2PhysicsUnit 11: Electrostatics

Positive electric flux indicates that electric lines of force are directed

Q3PhysicsUnit 11: Electrostatics

Which of the following statements is not true about Gauss's law?

Q4PhysicsUnit 11: Electrostatics

The Sl unit of electric flux density is

Q5PhysicsUnit 11: Electrostatics

The Gaussian surface for calculating the electric field due to a charge distribution is

Q6PhysicsUnit 11: Electrostatics

The total number of lines of force passing through a surface is called

Q7PhysicsUnit 11: Electrostatics

If the electric flux entering and leaving a closed surface are

6 \times 10^{6}

and

9 \times

10^{6} S I

units respectively, then the charge inside the surface of permittivity of free space

\omega_{0}

Q8PhysicsUnit 11: Electrostatics

If an electric dipole is placed inside a sphere filled with water, then among the following which statement is correct?

Q9PhysicsUnit 11: Electrostatics

An electric dipole is placed at the centre of a sphere. Mark the correct options:

Q10PhysicsUnit 11: Electrostatics

A closed surface S is constructed around a conducting wire connected to a battery and switch (Fig) As the switch is closed, the free electrons in the wire start moving along the wire. In any time interval, the number of electrons entering the closed surface

S

is equal to the number of electrons leaving it. After closing the switch, the flux of the electric field through the closed surface will : This question has multiple correct options

Q11PhysicsUnit 11: Electrostatics

If the electric field is given by

(5 i+

4 j+9 k),

the electric flux through a surface of area 20 unit lying in the

Y-Z

plane will be :

Q12PhysicsUnit 11: Electrostatics

The black shapes in the figure are closed surfaces. The electric field lines are in red. For which case the net flux through the surfaces is non-zero? (b)

(c)

Q13PhysicsUnit 11: Electrostatics

A Gaussian surface in the figure is shown by dotted line. The electric field on the surface will be:

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