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Hard Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units MCQs for JEE

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Hard Elementary and complex reactions, order and molecularity of reactions, rate law, rate constant and its units MCQs train multi-concept problem solving — attempt after mastering easy and medium sets (7+ on Goodmarks).

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Q1ChemistryUnit 8: Chemical Kinetics
A reaction A+BCA+B \rightarrow C is second order with respect to AA and independent of BB The rate expression for the reaction is:
Q2ChemistryUnit 8: Chemical Kinetics
Statement - I : The molecularity of the reaction H2+Br22HBr\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow 2 \mathrm{HBr} is 2 Statement - II: The order of this reaction is 3/23 / 2
Q3ChemistryUnit 8: Chemical Kinetics
The choices below are some of the proposed steps of a reaction mechanism. Which step is least likely to be the ratedetermining step of the mechanism?
Q4ChemistryUnit 8: Chemical Kinetics
Which one of the following statements for order of reaction is not correct?
Q5ChemistryUnit 8: Chemical Kinetics
In the hydrolysis of organic chloride in the presence of a large excess of water, RCl+H2OROH+HCl\boldsymbol{R C l}+\boldsymbol{H}_{2} \boldsymbol{O} \rightarrow \boldsymbol{R O H}+\boldsymbol{H} \boldsymbol{C l}
Q6ChemistryUnit 8: Chemical Kinetics
For the reaction given below, 2O3(g)3O2(g)\mathbf{2} \mathbf{O}_{\mathbf{3}}(\mathbf{g}) \rightarrow \mathbf{3} \mathbf{O}_{\mathbf{2}}(\mathbf{g}) Step:O3(g)O2(g)+O(g)\operatorname{Step} \mid: \mathbf{O}_{3}(\mathbf{g}) \rightarrow \mathbf{O}_{2}(\mathbf{g})+\mathbf{O}(\mathbf{g}) Step 2:O3(g)+Oslow 2O2(g)2: \mathrm{O}_{3}(\mathrm{g})+\mathrm{O} \rightarrow^{\text {slow }} 2 \mathrm{O}_{2}(\mathrm{g}) Statement I: The molecularity of the first step is 1 and of the second step is 2 Statement-II: O(g)O(g) is an intermediate and rate of reaction is K[O3]2[O2]1\mathbf{K}\left[\mathbf{O}_{3}\right]^{2}\left[\mathbf{O}_{2}\right]^{-1} and order of reaction is 1
Q7ChemistryUnit 8: Chemical Kinetics
Which of the following statement is true for the reaction, H2+Br22HBr\boldsymbol{H}_{2}+\boldsymbol{B} \boldsymbol{r}_{2} \rightarrow \boldsymbol{2} \boldsymbol{H} \boldsymbol{B} \boldsymbol{r} The rate law is dxdt=k[H2][Br2]1/2\frac{\boldsymbol{d} \boldsymbol{x}}{\boldsymbol{d} \boldsymbol{t}}=\boldsymbol{k}\left[\boldsymbol{H}_{2}\right]\left[\boldsymbol{B} \boldsymbol{r}_{2}\right]^{1 / 2}

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