Physics · JEE

Motion in a plane, projectile motion, uniform circular motion Concepts for JEE

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Quick answer

Master Motion in a plane, projectile motion, uniform circular motion by understanding definitions, standard results, and typical JEE question patterns — then practise with syllabus-aligned MCQs on Goodmarks.

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Concept explainer

Motion in a plane, projectile motion, uniform circular motion is a core JEE Main Physics subtopic under Kinematics. Master the definitions, standard results, and typical MCQ patterns tested in JEE Main and Advanced.

Key points

  • Understand the definition and scope of Motion in a plane, projectile motion, uniform circular motion in the JEE syllabus
  • Memorise key formulas and standard results linked to Motion in a plane, projectile motion, uniform circular motion
  • Practise 20–40 syllabus-aligned MCQs with step-by-step solutions

JEE tips

  • Revise Motion in a plane, projectile motion, uniform circular motion with a one-page formula sheet before attempting mixed tests
  • After each practice set, log mistakes specific to Motion in a plane, projectile motion, uniform circular motion and reattempt after 48 hours

Common trap

Students often rush Motion in a plane, projectile motion, uniform circular motion questions without checking units, sign conventions, or boundary conditions — always verify assumptions before calculating.

Free sample questions

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Q1PhysicsUnit 2: Kinematics
If the angle between the vectors A\vec{A} and B\vec{B} is θ,\theta, then the value of the product (B×A)A(\vec{B} \times \vec{A}) \cdot \vec{A} equals
Q2PhysicsUnit 2: Kinematics
A ball is thrown from the top of a tower with an initial velocityof 10m/s10 \mathrm{m} / \mathrm{s} at an angle of 3030^{\circ} above the horizontal. It hits theground at a distance of 17.3m17.3 \mathrm{m} from the base of the tower.The height of the tower (g=10m/s2)\left(\mathrm{g}=10 \mathrm{m} / \mathrm{s}^{2}\right) will be
Q3PhysicsUnit 2: Kinematics
A body is projected with velocity 24ms124 m s^{-1} making an angle 3030^{\circ} with the horizontal. The vertical component of its velocity after 2s2 s is (g=10ms2)\left(g=10 m s^{-2}\right)
Q4PhysicsUnit 2: Kinematics
A person travels 6m6 \mathrm{m} towards the east and 8m8 \mathrm{m} towards north from there again he traveled 16m16 \mathrm{m} towards the south. What is the displacement covered by the person?
Q5PhysicsUnit 2: Kinematics
An aeroplane flying at a constant speed releases a bomb. As the bomb moves away from the aeroplane, it will
Q6PhysicsUnit 2: Kinematics
Q Type your question. moving horizontally with a speed uu perpendicular to the direction of vv enters through a hole at an upper corner AA and strikes the diagonally opposite corner BB. Assume g=10m/s2.g=10 m / s^{2} . Which of the following values of uu and vv is(are) correct? This question has multiple correct options
Q7PhysicsUnit 2: Kinematics
A particle projected from the origin (x=y=0)(x=y=0) moves in xyx y plane so that its velocity is v=(2i^+4xj^)m/s,v=(2 \hat{i}+4 x \hat{j}) \mathrm{m} / \mathrm{s}, when it is at point (x,y)(x, y) m. (i^ and j^(\hat{i} \text { and } \hat{j} are the unit vectors along xx and yy axis). What is the value of y,y, when x=3x=3
Q8PhysicsUnit 2: Kinematics
Assertion In case of a projectile, the angle between velocity and acceleration changes from point to point. Reason Because its horizontal component of velocity remains constant, while vertical component of velocity changes from point to point due to gravitational acceleration.

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